Split the words using string tokenizer if it is followed by two or more space/whitespace in java?

Question

In my string, i want to tokenize string on the basis of two or more spaces.

E.x.

String str = "I am  Chaitanya Gadam.      Split   this string."
StringTokenizer tokenizer = new StringTokenizer(str);
while (tokenizer.hasMoreTokens()) 
{
    String token = tokenizer.nextToken();
    System.out.println("==Token== : "+token);
}

I am getting out put as :

==Token== : [I]
==Token== : [am]
==Token== : [Chaitanya]
==Token== : [Gadam.]
==Token== : [split]
==Token== : [this]
==Token== : [string.]

But desired Output should be :

==Token== : [I am]
==Token== : [Chaitanya Gadam.]
==Token== : [split]
==Token== : [this string.]

Rahul · Accepted Answer · 2013-04-03T08:32:20.310

2

You can use this regex in the String.split(regex) method.

String[] tokens = str.split("  +");

Update:-

If you need to remove the leading and trailing white spaces, trim() it and then split your String.

str = str.trim();

edited Apr 03 '13 at 08:32

answered Apr 03 '13 at 07:33

Rahul

44,383
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Another problem is that if my string have extra white space at the begining then i get output as, final String src = " I am Chaitanya Gadam. Split this srting."; [, I am, Chaitanya Gadam., Split, this srting.] – Chaitanya Gadam Apr 03 '13 at 08:28
but reqiured output is [I am, Chaitanya Gadam., Split, this srting.] So i am trying to use string tokenizer. – Chaitanya Gadam Apr 03 '13 at 08:30
Check my update. Use `trim()`. – Rahul Apr 03 '13 at 08:32

score 0 · Answer 2 · answered Apr 03 '13 at 07:28

0

This should work-

    String[] array = str.split("\\s{2,}");
    for (String word : array) {
        System.out.println(word);
    }

answered Apr 03 '13 at 07:28

Sudhanshu Umalkar

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Split the words using string tokenizer if it is followed by two or more space/whitespace in java?

2 Answers2