Bytebuffer in Java

Question

I send long number via UDP.

    LinkedQueue Q = new LinkedQueue<ByteBuffer>();
    while (this._run) {
    udp_socket.receive(packet);
      if (packet.getLength() > 0) {
       ByteBuffer bb = ByteBuffer.wrap(buf, 0, packet.getLength());     
               Q.add(bb);
          }
    }

//udp close. I remove data from Queue, but all ByteBuffers have same value.

    while(!Q.isEmpty){
      ByteBuffer b = Q.remove();
      b.getLong();//same value
    }

Why i receive same value? Any Suggest?

Question is :I remove data from Queue, but all ByteBuffers have same value. — Suresh Atta, Apr 02 '13 at 15:28
Are you reusing the same `buf` object? And you don't seem to take any data from the `packet` either? — maba, Apr 02 '13 at 15:30
I debugged: all b that removed from Q has same backingarray id — Anh Tuan, Apr 02 '13 at 15:31

score 1 · Answer 1 · answered Apr 02 '13 at 15:33

Does your byte buffer consists of just one long?

Probably not, my guess is that you put a bit too much for just one long in there. And that's why it gives you same values on first sizeof(long) bytes.

What you need to do is to keep calling .getLong() until you hit the end of the buffer.

See the docs.

Bytebuffer in Java

1 Answers1