JSON string with some html tag failing at parse

Question

I am taking user input sending it to server using jQuery ajax...after inserting user values in database I am sending response back to client as JSON string as following

echo '{"success":"true","data":"'.nl2br($a).'","type":"text"}';

as user input can contain new line, I am using nl2br so that all new line characters are converted to <br> and also know that JSON doesnt support multi line, thats why I am using nl2br....but parsing is failing at client side

pls tell me what the reason and how can I solve it?

parsing code var obj = jQuery.parseJSON(data);

`{"success":"true","data":"adad
dadad","type":"text"}` this my response at client side — vikas devde, Apr 01 '13 at 19:20
doesnt show any error....but anything ahead parsing line is not getting executed,,,that parsing statement is not getting executed — vikas devde, Apr 01 '13 at 19:22
When you log the JSON string in the console on the client side, does it log exactly the JSON you pasted? Could you show the parsing code? — plalx, Apr 01 '13 at 19:26
`jQuery.parseJSON('{"success":"true","data":"adad
dadad","type":"text"}')` works fine, wich suggests that the JSON your client recieves is not what you pasted. Are you sure the code gets executed at all? — plalx, Apr 01 '13 at 19:33

score 1 · Answer 1 · answered Apr 01 '13 at 19:21

1

echo json_encode(array("success"=>"true","data"=>$a,"type"=>"text")

Use the php function json_encode rather then trying to set the encoding yourself. You'll save yourself a lot of trouble that way. http://php.net/manual/en/function.json-encode.php

answered Apr 01 '13 at 19:21

AlexLordThorsen

8,057
5
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I am getting this string as response `{"success":"true","data":"dada\r\ndada\r\nada","type":"text"}` i think here I need to replace all \r\n to
....?? – vikas devde Apr 01 '13 at 19:29

Jason McCreary · Answer 2 · 2013-04-01T20:39:20.270

1

nl2br() does not replace the line breaks, only inserts <br> before them.

As such, \n is being returned and therefore creating invalid JSON.

You should use json_encode() when creating JSON strings. For simplicity, you could simply use it on data:

echo '{"success":"true","data":' . json_encode(nl2br($a)) . ',"type":"text"}';

edited Apr 01 '13 at 20:39

answered Apr 01 '13 at 19:22

Jason McCreary

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Ok let me try first that...I will get back to you – vikas devde Apr 01 '13 at 19:23
I am getting this `{"success":"true","data":"dada
\r\ndada
\r\nada","type":"text"}` – vikas devde Apr 01 '13 at 19:32

score 1 · Accepted Answer · answered Apr 01 '13 at 20:06

You should be using json_encode, wich will generate a JSON string that contains \r\n for line breaks. Then you will have to replace each \r\n occurences by <br> tags.

echo str_replace('\r\n','<br>', json_encode(array("success"=>"true","data"=>$a,"type"=>"text")));

JSON string with some html tag failing at parse

3 Answers3