Cropping an uploaded image with Java

Question

I am reading a image file in a servlet from an http request. I want to crop it as a square and write it to file. I can achieve that with the following code but i am using a temporary file to write the original image first. How can I do that without using a temp file

                    File tempFile = new File(saveFileFrameTemp);
                    fileOut = new FileOutputStream(tempFile);
                    fileOut.write(dataBytes, startPos, (endPos - startPos));
                    fileOut.flush();
                    fileOut.close();

                    BufferedImage fullFrame = ImageIO.read(tempFile);
                    int height = fullFrame.getHeight();
                    int width = fullFrame.getWidth();
                    if (height > width)
                        ImageIO.write( fullFrame.getSubimage(0, (height-width)/2, width, width), "jpg", new File(saveFileFrame));
                    else
                        ImageIO.write( fullFrame.getSubimage((width-height)/2, 0, height, height), "jpg", new File(saveFileFrame));

                    tempFile.delete();

score 0 · Answer 1 · answered Apr 01 '13 at 17:22

0

You cannot crop a BufferedImage without creating a new BufferedImage as a side effect

answered Apr 01 '13 at 17:22

CodeGuy

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thats OK all I want is not to create a temp file and extra disk io – Nuri Tasdemir Apr 01 '13 at 17:36

score 0 · Accepted Answer · answered Apr 01 '13 at 18:29

I solved it using ByteArray.

ByteArrayOutputStream baos = new ByteArrayOutputStream();
baos.write(dataBytes, startPos, (endPos - startPos));

BufferedImage fullFrame = ImageIO.read(new ByteArrayInputStream(baos.toByteArray()));

And I used this link in the process http://www.mkyong.com/java/how-to-convert-byte-to-bufferedimage-in-java/

Cropping an uploaded image with Java

2 Answers2