Create a list of process ordered by status

Question

I need create a shell script to list the process by status type. The output must be something like:

Process running:

[process]

Process sleeping:

[process]

ETC

I did this, but doesnt work the ps aux | awk '$8 ~ PROCESS':

for PROCESS in `ps -v | awk 'NR!=1 {print $2}' | sort -u`; do
   echo "Procesos como $PROCESS:"
   ps aux | awk '$8 ~ PROCESS'
done

Cause that script outputs all the process, not filter by Process.

Any help?

first of all there is a typo, you missing $ **ps aux | awk '$8 ~ $PROCESS'** — Satish, Apr 01 '13 at 15:39

salezica · Answer 1 · 2013-04-01T15:44:57.053

1

A simple solution would be to use ps and sort:

ps u | sort -rk 8

-r reverses the sort (so that the list header remains above), and -k 8 selects the 8th field (STAT).

You can then select processes in a specific state using anything form head to awk, and print out whatever you like.

edited Apr 01 '13 at 15:44

answered Apr 01 '13 at 15:39

salezica

without **sort -rk 8** i am getting same output – Satish Apr 01 '13 at 15:43
By default, `ps` sorts by `PID`. You may have `ps` aliased, or it may be coincidence – salezica Apr 01 '13 at 15:46
uʍop ǝpısdn : Doesn´t works: ps u | sort -rk 8 return me just the same process each time, and they arent filter by process – Alberto Fortes Apr 01 '13 at 15:56

score 0 · Answer 2 · answered Apr 01 '13 at 17:41

0

You can also use top, in non-interactive mode ( the -S option to display and sort by state):

top -b -n 1 -S

answered Apr 01 '13 at 17:41

b2Wc0EKKOvLPn

But How I pass the variable for each process? I have to use awk after. the real problem is: awk '$8 ~ PROCESS' doesnt work – Alberto Fortes Apr 01 '13 at 19:10
The command below works pretty fine for me, it extracts the pid, the state, and the process name: `top -b -n 1 -S | awk '{print $1 " " $8 " " $12}'` – b2Wc0EKKOvLPn Apr 01 '13 at 19:48

2 Answers2