1

I would like to trim a string in Lua but I'm struggling I think because of the special characters in the string.

E.g. str = "RG Ph 0%/15.00bpm"

I would like to remove everything after and including the "/"

so thatstr = "RG Ph 0%"

I have found the following code but I don't think it handles the "%" and "/" properly:

local string_gsub = string.gsub

function string.trimRight( str, char )          
char = char or "%s"          
return ( string_gsub( str, "(" .. char .. "*)$", "" ) )  
end

Any ideas?

Yu Hao
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user2219340
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1 Answers1

2
local str = "RG Ph 0%/15.00bpm"
str = str:match'[^/]*'
print(str)
Egor Skriptunoff
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