So we were working this problem in class and for f(2) I got the same answer but for f(3) I got something different from the professor.
Basis: f(0) = -1 and f(1) = 2
Recursion: f(n) = f(n-2) - f(n-1)
For f(3) I am getting 1
f(3-2) - f(3-1)
=f(1) - f(2)
=2 - f(2-2) - f(2-1)
=2 - -1 - 2
=2+1-2 = 1
But the answer he got was:
5