XSLT Transforming: Select distinct and appendchild group

Question

<Sections>
    <Products>
      <Transport>
        <TransportSequence>1</TransportSequence>
        <Traveller>001</Traveller>
      </Transport>
      <Transport>
        <TransportSequence>2</TransportSequence>
        <Traveller>001</Traveller>
      </Transport>
    </Products>
  </Sections>
  <Sections>
    <Products>
      <Transport>
        <TransportSequence>1</TransportSequence>
        <Traveller>002</Traveller>
      </Transport>
      <Transport>
        <TransportSequence>2</TransportSequence>
        <Traveller>002</Traveller>
      </Transport>
    </Products>
  </Sections>

I have a specific problem with the ordering of some XML. From the above example I need to change the format so that I select distinct only on the TransportSequence. I then need to assign any 'Traveller' nodes as children to produce something like this:

<Sections>
   <Products>
      <Transport>
         <TransportSequence>1</TransportSequence>
         <Travellers>
            <Traveller>001</Traveller>
            <Traveller>002</Traveller>
         </Travellers>
      </Transport>
      <Transport>
         <TransportSequence>2</TransportSequence>
         <Travellers>
            <Traveller>001</Traveller>
            <Traveller>002</Traveller>
         </Travellers>
      </Transport>
   </Products>
</Sections>

The other problem is that in the Transport node also contains lots of children and grandchildren nodes not shown in this example. There can also be many travllers belonging to a TravellerSequence. There are also many TransportSequence numbers.

Do you want to use XSLT 1.0 or 2.0? Grouping is easier in XSLT 2.0 with `for-each-group`. — Martin Honnen, Mar 26 '13 at 13:58

Martin Honnen · Accepted Answer · 2013-03-26T14:13:44.873

Here is an XSLT 2.0 stylesheet to be run with XSLT 2.0 processors like Saxon 9 or AltovaXML:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="2.0">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="*[Sections]">
  <xsl:copy>
    <Sections>
      <Products>
        <xsl:for-each-group select="Sections/Products/Transport" group-by="TransportSequence">
          <Transport>
            <TransportSequence><xsl:value-of select="current-grouping-key()"/></TransportSequence>
            <Travellers>
              <xsl:copy-of select="current-group()/Traveller"/>
            </Travellers>
          </Transport>
        </xsl:for-each-group>
      </Products>
    </Sections>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

It transforms

<Root>
<Sections>
    <Products>
      <Transport>
        <TransportSequence>1</TransportSequence>
        <Traveller>001</Traveller>
      </Transport>
      <Transport>
        <TransportSequence>2</TransportSequence>
        <Traveller>001</Traveller>
      </Transport>
    </Products>
  </Sections>
  <Sections>
    <Products>
      <Transport>
        <TransportSequence>1</TransportSequence>
        <Traveller>002</Traveller>
      </Transport>
      <Transport>
        <TransportSequence>2</TransportSequence>
        <Traveller>002</Traveller>
      </Transport>
    </Products>
  </Sections>
</Root>

into

<Root>
   <Sections>
      <Products>
         <Transport>
            <TransportSequence>1</TransportSequence>
            <Travellers>
               <Traveller>001</Traveller>
               <Traveller>002</Traveller>
            </Travellers>
         </Transport>
         <Transport>
            <TransportSequence>2</TransportSequence>
            <Travellers>
               <Traveller>001</Traveller>
               <Traveller>002</Traveller>
            </Travellers>
         </Transport>
      </Products>
   </Sections>
</Root>

[edit] To complete the answer, if you want to use an XSLT 1.0 processor, a solution using Muenchian grouping looks as follows:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="by-seq" match="Sections/Products/Transport" use="TransportSequence"/>

<xsl:template match="*[Sections]">
  <xsl:copy>
    <Sections>
      <Products>
        <xsl:for-each select="Sections/Products/Transport[generate-id() = generate-id(key('by-seq', TransportSequence)[1])]">
          <Transport>
            <xsl:copy-of select="TransportSequence"/>
            <Travellers>
              <xsl:copy-of select="key('by-seq', TransportSequence)/Traveller"/>
            </Travellers>
          </Transport>
        </xsl:for-each>
      </Products>
    </Sections>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Many thanks, this is pointing me in the right direction and has solved a lot of problems. — BerZerK, Mar 26 '13 at 16:13

XSLT Transforming: Select distinct and appendchild group

1 Answers1