django url get method urlpatterns

Question

Page not found (404)
Request Method: GET
Request URL: http://chinafhp.sinaapp.com/search/?q=ag

urlpatterns:

urlpatterns = patterns('',
    # Examples:
    # url(r'^$', 'web.views.home', name='home'),
    # url(r'^web/', include('web.foo.urls')),

    # Uncomment the admin/doc line below to enable admin documentation:
    # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:

    url(r'^serach/$',views.serach),
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$',views.home),

    url(r'^movie/([^/]+)/$',views.movieList),
    url(r'^tv/([^/]+)/$',views.tvList),
)

why?

maybe because you spelled it wrong? – Hedde van der Heide Mar 24 '13 at 09:31 — Hedde van der Heide, Mar 24 '13 at 09:31

score 4 · Answer 1 · answered Mar 24 '13 at 09:34

4

url(r'^serach/$',views.serach),

should be

url(r'^search/$',views.search),

answered Mar 24 '13 at 09:34

xuanji

5,007
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score 1 · Answer 2 · answered Mar 24 '13 at 10:16

1

Seems you misspelled search word there, But the thing is you entered views.serach correctly, because django didn't complain about it so there is a serach view definitively.

So if you want to access you url you will be fine by:

http://chinafhp.sinaapp.com/serach/?q=ag

answered Mar 24 '13 at 10:16

Alireza Savand

3,462
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actually, http://chinafhp.sinaapp.com/search/?q=ag seems to be fine now – xuanji Mar 24 '13 at 10:32

django url get method urlpatterns

2 Answers2