Is there an "AllIndexesOf" method?

Question

Background:

I'm working on an evaluator (I know there's solutions available, but I need some features that I need to implement myself). I need to find all occurrences of open brackets in the evaluation. However, for that I need all the indexes of the brackets.

Question:

Is there something like an AllIndexesOf method that returns a int[], or IEnumerable<int>?

Why close votes? I get duplicate votes, but why close votes. Btw, title was so different I missed it, thanks Tim! — It'sNotALie., Mar 20 '13 at 08:07
_"I get duplicate votes, but why close votes"_ Duplicate votes **are** close votes. — Tim Schmelter, Mar 20 '13 at 08:41
I haven't downvoted but this question was asked many times even if in slightly different contextes. [google](http://tinyurl.com/dyqk3jl) — Tim Schmelter, Mar 20 '13 at 08:47

score 8 · Accepted Answer · answered Mar 20 '13 at 07:59

There is not but you can get all the indexes using the following LINQ query.

int number  = 10;
int[] intArray = new[] { 1, 32, 10, 5, 65, 6, 10, 10 };
var allIndexes = intArray.Select((r,i)=> new {value = r, index = i})
                         .Where(r=> r.value == number)
                         .Select(r=> r.index);

allIndexes will contain 2,6 and 7

cuongle · Answer 2 · 2013-03-20T08:17:52.857

4

You also can use Enumerable.Range

 var indexes = Enumerable.Range(0, list.Count)
                         .Where(index => list[index] == yourValue);

edited Mar 20 '13 at 08:17

answered Mar 20 '13 at 08:03

cuongle

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That's quite clean. Thanks! – It'sNotALie. Mar 20 '13 at 08:04

Is there an "AllIndexesOf" method?

2 Answers2