Int cannot be deferenced error

Question

I am trying to take the user input from one method and use it in another. I am confused about the error because they are both of type int.

public static void move()
{
    System.out.println("What do you want to do?");
    Scanner scan = new Scanner(System.in);
    int userMove = scan.nextInt();
}

public static void usersMove(String playerName, int gesture)
{
    int userMove = userMove.move(); //error is here

    if (userMove == -1)
    {
        break;
    }

move() has return type as void, make it int and return the value. — Sudhanshu Umalkar, Mar 20 '13 at 07:42
@Sudhanshu - even then its wrong. You can't call a method on a primitive data type. — Rahul, Mar 20 '13 at 07:43
I was assuming that userMove is an object, otherwise you are right. May be he has messed up the names in the post. — Sudhanshu Umalkar, Mar 20 '13 at 07:43
Actually, the OP wants to call the `move()` method to get the value for `userMove`, which is an `int`. Must have got confused on how to call that method, and hence, the error. — Rahul, Mar 20 '13 at 07:44
Yes, even move() needs to return that value and change its return type to int. — Sudhanshu Umalkar, Mar 20 '13 at 07:53

score 6 · Accepted Answer · answered Mar 20 '13 at 07:39

6

int userMove = userMove.menu();

userMove here is an int(primitive data type). How can you call a method on that?

I'm guessing that you want something like this:-

public static int move()
{
    System.out.println("What do you want to do?");
    Scanner scan = new Scanner(System.in);
    int userMove = scan.nextInt();
    return userMove;
}

public static void usersMove(String playerName, int gesture)
{
    int userMove = move(); //Now error will go.

    if (userMove == -1)
    {
        break;
    }

answered Mar 20 '13 at 07:39

Rahul

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I am now getting an incompatible type area. Is this because of my return statement? int userMove = menu(); ^ required: int found: void – user2181402 Mar 20 '13 at 07:45
Your `menu()` method should also return `int` because its return value assigned to `userMove`. – Wayan Wiprayoga Mar 20 '13 at 07:46
see my answer. I've changed the return value of `move()` method. Make that change too. – Rahul Mar 20 '13 at 07:46

score 0 · Answer 2 · answered Mar 20 '13 at 07:41

Just guessing, since it is not clear what userMove is... but you seem to use a variable from another method in the caller. You need to return it to do that

public static int move()
{
   System.out.println("What do you want to do?");
   Scanner scan = new Scanner(System.in);
   return scan.nextInt();
}

public static void usersMove(String playerName, int gesture)
{
   int userMove = move(); //error is here

   if (userMove == -1)
   {
       break;
   }

Int cannot be deferenced error

2 Answers2