Which coder should I use to code a long property using NSCoder?

Question

I have an object I must encode using encodewithcoder but it's a 'long' number and I'm not sure if I must encode it like a simple int, a int32 or a int64. Apple's documentation doesn't seems to be useful for me to figure out since it never refers to 'long' type.

Which coder is the proper one?.

Thank you

Assuming its impossible to change your property to a known width primitive like int32_t or similar? — nielsbot, Mar 19 '13 at 05:06
This property is defined in the documentation I've received from the client (a big enterprise). I really don't know what is this property supposed to store. — rmvz3, Mar 19 '13 at 05:52

score 3 · Accepted Answer · answered Mar 19 '13 at 05:00

3

For iOS, a long is 32-bits, same as an int. long long gives you 64-bits.

long someVar = 42l;
[someEncoder encodeInt32:someVar forKey:@"someKey"];

answered Mar 19 '13 at 05:00

rmaddy

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Wow!. That was fast!. Thank you. – rmvz3 Mar 19 '13 at 05:01
Hmm, encoding a `long` with `encodeInt32` gives me a loss of precision warning - but not when using `encodeInt64`. – Jeshua Lacock Sep 16 '16 at 04:26

Which coder should I use to code a long property using NSCoder?

1 Answers1