How to run junit 3 with non default constructor

Question

I have a code base where they define junit test cases as :

public class MyTest extends BaseTestCase
{
    public MyTest( String name )
    {
        super( name );
    }

    public void testSome() throws Exception
    {
        assertTrue (1 == 1);
    }
}

How to do I run this test from eclipse? How do I supply the name in the constructor?

new MyTest("testSome")).run(); from some eclipse main file ? — Shmil The Cat, Mar 13 '13 at 21:49

GuessBurger · Answer 1 · 2013-03-13T22:23:29.627

2

If you are creating the implementation the why not pass the super types construction parameter yourself i.e.

public class MyTest extends BaseTestCase
{
    public MyTest()
    {
        super( "My Test" );
    }

    public void testSome() throws Exception
    {
        assertTrue (1 == 1);
    }
}

edited Mar 13 '13 at 22:23

answered Mar 13 '13 at 22:05

GuessBurger

478
4
9

I think you meant to remove the parameter to the MyTest constructor? – sharakan Mar 13 '13 at 22:22

score 1 · Answer 2 · answered Mar 13 '13 at 21:59

You can't run it directly as JUnit runner expect 'Test class should have exactly one public zero-argument constructor' so you have to invoke it manually or as @shim cat have shown or do this per class

protected void setUp() throws Exception {
    System.out.println(" local setUp ");
}
protected void tearDown() throws Exception {
    System.out.println(" local tearDown ");
}

but if you want to share it you can do this per 'TestSuite'

protected void setUp() throws Exception {
    System.out.println(" Global setUp ");
}
protected void tearDown() throws Exception {
    System.out.println(" Global tearDown ");
}

How to run junit 3 with non default constructor

2 Answers2