what' the simplest way to bind my grid view on one record(distinct different data)

Question

What's the simplest way to bind my grid view to a single data row :

I have the following data for example :

dep_code = 3;
dep_name = "computer science";
boss_num = 356;
boss_name ="Ahmed";

i want to bind those data on my gridview.

What have you tried, what was the problem? Why do you need a `GridView` for a single record? You can use a `DetailsView` or `FormView`. — Tim Schmelter, Mar 13 '13 at 08:36
i have 4 values like the above , and i want to bind them on my grid view(one record) , can i use anonymous object or some way!! or i have to create a data table — Anyname Donotcare, Mar 13 '13 at 08:38
I think the most easiest way is to create a `DataTable`. As your `GridView` probably has column headers to? Which can be defined in your `DataTable` as well. — Mike de Klerk, Mar 13 '13 at 08:39
@just_name: You can create a `DataTable` or an anonymous type, both approaches are pretty easy, so i don't understand the problem. — Tim Schmelter, Mar 13 '13 at 08:39

score 2 · Accepted Answer · answered Mar 13 '13 at 08:34

2

I think List of list should be simplest

List<List<string>> list = {{dep_code,dep_name,boss_num,boss_name}};
GridView1.DataSource = list;
GridView1.DataBind();

answered Mar 13 '13 at 08:34

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1 Answers1