XLRD and HTTP Excel Files in Python

Question

Can I read directly from an HTTP location for use with xlrd?

I've tried the following:

import ntlm, urllib2
url = 'http://myurl/file.xls'
passman.add_password(None, url, login, password)
auth_NTLM = HTTPNtlmAuthHandler.HTTPNtlmAuthHandler(passman)
opener = urllib2.build_opener(auth_NTLM)
sock = urllib2.urlopen(url)
content = sock.read()

and have a function ReadFromExcel that reads an Excel file and returns some data, but it can't read from content.

ReadFromExcel(content) 
    book = xlrd.open_workbook(filename)
  File "C:\Python27\lib\site-packages\xlrd\__init__.py", line 400, in open_workbook
    f = open(filename, "rb")
TypeError: file() argument 1 must be encoded string without NULL bytes, not str

any ideas?

looks like it is! file_content is what I needed. thanks! – pedram Mar 11 '13 at 19:52 — pedram, Mar 11 '13 at 19:52

score 3 · Accepted Answer · edited May 23 '17 at 12:14

3

You should pass a file name instead of file's content:

import os
import tempfile

with tempfile.NamedTemoraryFile(suffix='.xls') as file:
    file.write(content)
    file.delete = False

try:
    result = ReadFromExcel(file.name)
finally:
    os.remove(file.name)

Or use file_contents parameter.

edited May 23 '17 at 12:14

Community

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answered Mar 11 '13 at 19:44

jfs

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XLRD and HTTP Excel Files in Python

1 Answers1