parse xml using xmllint

Question

I have an xml file as shown below. I want to use xmllint to parse it such that if the category is "SciFi", it will display the "isbn" number.

After struggling a bit I could figure out how to print only the category or only the isbn number ; but cannot figure out how to add the condition.

<book>
 <name>
  <category>SciFi</category>
  <isbn>12345678</isbn>
 </name>
 <name>
  <category>Mystery</category>
  <isbn>23456789</isbn>
 </name>
<book>

Edit : The version of xmllint I have does not support xpath

I made a mistake in my original post ; corrected xml above

xmllint --version produces

xmllint: using libxml version 20626

I use the following commands to print the information

cat /book/name[1]/category
cat /book/name[2]/category

cat /book/name[1]/isbn
cat /book/name[2]/isbn

Why not switch to a newer version (or even another program) that does support xpath? — BeniBela, Mar 09 '13 at 18:53
And how do I justify that to the support team to get it installed on some 1000+ Linux servers ? — souser, Mar 09 '13 at 19:05
What version of xmllint are you using and how are you printing only the `category` or `isbn`? — Daniel Haley, Mar 09 '13 at 20:28

score 0 · Accepted Answer · answered Mar 11 '13 at 22:52

0

This sounds like a poor tool for the purpose. If you have xmllint installed, do you have xsltproc? That would be more useful, I think.

Also, just to be sure, have you tried cat /book/name[category='SciFi']/isbn ?

answered Mar 11 '13 at 22:52

Mike Sokolov

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parse xml using xmllint

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