Print Current Statement in GDB

Question

Each time I step with n it prints out the next statement to be executed.

How do I see the next statement to be executed, as if I had typed n, but without actually stepping the code?

Currently I am using where, and this gives me the line number of the next statement and I can use list to see some source code. Does it require two separate commands to get what I want?

Also consider running `gdb --tui` – nos Mar 08 '13 at 23:17 — nos, Mar 08 '13 at 23:17

score 2 · Answer 1 · answered Aug 07 '13 at 07:11

2

Try "frame" command. You will see something like this:

   (gdb) frame
   #0 main () at dummy.c:11
   11    FILE*f = fopen("somefile","r");
   (gdb)

answered Aug 07 '13 at 07:11

olegst

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score 1 · Accepted Answer · answered Mar 08 '13 at 11:45

1

Define yourself a macro in your .gdbinit in your home-directory.

define shownext
where
list
end

Well, I am not sure if what I stated works out, but see here on how to do things like this.

answered Mar 08 '13 at 11:45

bash.d

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For some reason running `list` twice in a row moves the code focus/window. – Mar 08 '13 at 11:46
@infact - this is the defined behaviour. The documentation states "If the last lines printed were printed with a list command, this prints lines following the last lines printed;" – borrible Mar 08 '13 at 11:51

scottt · Answer 3 · 2013-03-09T23:14:09.420

If your gdb was built with Python support, this list.current.py script would add a new list-current gdb command that does what you want.

Sample session:

$ gdb -x list-current.py /bin/true
(gdb) start
Temporary breakpoint 1 at 0x4014c0: file true.c, line 59.
Starting program: /usr/bin/true 

Temporary breakpoint 1, main (argc=1, argv=0x7fffffffde88) at true.c:59
59    if (argc == 2)
(gdb) list-current 
59    if (argc == 2)
(gdb) list-current  3
59    if (argc == 2)
60      {
61        initialize_main (&argc, &argv);
(gdb) list-current  -2
58       argument.  */
59    if (argc == 2)
(gdb)

Print Current Statement in GDB

3 Answers3