Interrupt handler declaration: armcc vs gcc

Asked Mar 07 '13 at 22:47

Active Mar 07 '13 at 23:18

Viewed 815 times

I want to declare an interrupt routine function.

Originally written for armcc as :

extern "C" __irq void System_FiqDispatcher() SECTION_SRAM_2;

I am writing the same as:

extern "C" __attribute__ (( interrupt("IRQ"))) void System_FiqDispatcher() SECTION_SRAM_2;

I got the following error: line XXX : Error: #1207-D: attribute "interrupt" ignored. What could be the problem?

edited Mar 07 '13 at 23:18

osgx

asked Mar 07 '13 at 22:47

aditya3524

I am compiling this using GNU GCC – aditya3524 Mar 07 '13 at 22:48
1

Why did you give it that attribute? Is that something GCC understands, even? – Carl Norum Mar 07 '13 at 22:59
I was throwing some error...let me check – aditya3524 Mar 07 '13 at 23:02
A-J, please, add full error message from GCC to the question. "Error 1207" is from armcc. – osgx Mar 07 '13 at 23:19
HwSystemMain.h:1168:12: error: '__irq' does not name a type...make[3]: *** [C:/code_coverage.o] Error 1 make[3]: *** Waiting for unfinished jobs.... – aditya3524 Mar 07 '13 at 23:22
@A-J, but you just said you changed that. Your supposed GCC example doesn't even have that `__irq` string in it at all! – Carl Norum Mar 07 '13 at 23:34
Well I got it resolved..Thanks osgx..I realized my mistake! I was compiling some part with armcc and the rest with gnu gcc...Just added a switch and now it is working fine! :-) – aditya3524 Mar 07 '13 at 23:40
Why did you tag this as C while using `extern "C"`? Are you compiling this in C or C++? – Lundin Mar 08 '13 at 10:31

0 Answers0