Can anyone explain output

Question

#define power(a) #a
  int main()
  {
    printf("%d",*power(432));
     return 0;
  }

can anyone explain the o/p??
the o/p is

52

What do you think it does? Have you made any effort understanding this code? It's trivial. — , Mar 02 '13 at 14:13
In that case you're in the most serious need of reading a basic C language tutorial. It's used for pointer dereferencing. — , Mar 02 '13 at 14:17
@akash in `power(432)` => `"432"` and `*"432"` => `"432"[0]` => `'4'` and because `%d` ascii value printed. Remember we do `char* ch = "432"` that means type of a string is `"432"` is `char*` so we can index using `[]`. as we can do `ch[]` Your **macro** convert macro function argument to string. because single `#` operator. — Grijesh Chauhan, Mar 02 '13 at 14:21

score 12 · Accepted Answer · answered Mar 02 '13 at 14:13

12

It is equivalent to:

printf("%d",*"432");

which is equivalent to:

printf("%d", '4');

and the ASCII value of '4' is 52.

answered Mar 02 '13 at 14:13

ouah

142,963
15
272
331

score 0 · Answer 2 · answered Mar 02 '13 at 17:38

#define power(a) #a   //# is a stringization operation in macro
  int main()
  {
    printf("%d",*power(432));
     return 0;
  }

Hence after calling power(432), macro will return it "432" and applying * on it gives first value which is nothing but 52 (48 + 4) for '4' .

Can anyone explain output

2 Answers2