Error (?) in Day counting PHP

Question

<?php
$date1 = "2002-1-1";
$date2 = "2021-12-31";
$deff = abs(strtotime($date2) - strtotime($date1));
$daycount = $deff / (60 * 60 * 24);
echo $daycount;
?>

Why the answer is 7304 instead of 7300 as I am trying to calculate the number of days for 20 years?

Please help.

Thanks friends. Yes the problem is of leap days. is there any way to get it exactly 7300 without manipulating later? I mean without counting the leap days. — user2095988, Feb 21 '13 at 15:46

score 2 · Answer 1 · answered Feb 21 '13 at 15:41

2

Use DateTime for this:

$datetime1 = new DateTime("2002-1-1");
$datetime2 = new DateTime("2021-12-31");
$interval  = $datetime1->diff($datetime2);
$elapsed   = $interval->format('%a days');
echo $elapsed;

See it in action

Reference

answered Feb 21 '13 at 15:41

John Conde

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I guess this means the output is correct. – John Conde Feb 21 '13 at 15:44
Sorry Mr. John Conde. It still returns 7304 days. – user2095988 Feb 21 '13 at 16:08

score 0 · Answer 2 · answered Feb 21 '13 at 15:41

0

You are forgetting leap years.

answered Feb 21 '13 at 15:41

Nanne

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score 0 · Answer 3 · answered Feb 21 '13 at 15:41

0

Your code is correct. That is how many days there are between the two days. Don't forget about leap years.

answered Feb 21 '13 at 15:41

mcryan

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score 0 · Answer 4 · edited Jun 20 '20 at 09:12

0

Dude, the answer is:

From and including: Tuesday, 1 January 2002

To, but not including : Friday, 31 December 2021

It is 7304 days from the start date to the end date, but not including the end date.

You forgot to add the leap years. That is the four extra days!!!

edited Jun 20 '20 at 09:12

Community

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answered Feb 21 '13 at 15:42

Praveen Kumar Purushothaman

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Error (?) in Day counting PHP

4 Answers4