replace in java using regular expression

Question

suppose I have a string

  String = ".... helllo.... good \"morning\" .....\" "

I want to get output as

  helllo good morning 

How can I do that using regular expression in Java?

Answer 1

If you're just trying to remove the . and the ", then you can do

 str = str.replaceAll("\"|\\.", "");

This regular expression replaces any " (escaped as \" because in a java string literal) or (|) . (escaped first as \. because in a regex then as \\. because a \ must be escaped in a java string literal) by nothing ("").

Answer 2

Supposing you just want to maintain the space character and letters, you can use the following regex:

[^a-zA-Z\s]+

If you also want to include numbers:

[^a-zA-Z0-9\s]+

Just replace the matches of that regular expression by an empty string.

Edit:

If you just want to do the opposite (remove certain characters, like . and "), then you can check @dystroy answer.

Answer 3

This

String yourString = ".... helllo.... good \"morning\" .....\" ";
System.out.println(yourString.replaceAll("[.\\\"]", ""));

outputs helllo good morning

Answer 4

public static void main(String[] args) {
    String str = ".... helllo.... good \"morning\" .....\" ";
    str = str.replaceAll("[^a-zA-Z]", " ").replaceAll("  +", " ");

    System.out.println(str);
}

Answer 5

There are many ways to do this.

Here is a way to do it using simple replace methods of String class.

    String s = ".... helllo.... good \"morning\" .....\" ";
    s = s.replace(".","").replace("\"", "");
    System.out.println(s);