Can someone explain the meaning of this 'typedef'?

Question

Can someone explain this typedef please?

typedef void (*_sig_func_ptr)(int);

Understanding its meaning seems critical to answering my question: MPICH2 compilation issue using Cygwin

It's a prototype for a function that has one `int` parameter and returns `void` — James, Feb 17 '13 at 21:36

score 3 · Accepted Answer · answered Feb 17 '13 at 21:36

3

it declares a type which is a function pointer which takes an int and returns void

can be used like :-

void blah(int x)
{
}


_sig_func_ptr ptr;

ptr = blah;  // make ptr point to blah

ptr(12);     // now we can call blah by using the function pointer

answered Feb 17 '13 at 21:36

Keith Nicholas

score 2 · Answer 2 · answered Feb 17 '13 at 21:36

2

This is the syntax of the typedef of a function pointer type.

Here _sig_func_ptr is an alias for the type void (*)(int).

An object of type _sig_func_ptr is a pointer to a function with one int parameter and that returns nothing.

answered Feb 17 '13 at 21:36

ouah

2 Answers2