Equivalent of ereg() call

Question

My server is running on php 5.3 now and I need to replace this call to ereg:

if (ereg("/$", $pref) === FALSE) 
{
  $pref .= '/';
}

I have tried this, among other things without any success:

if (preg_match('~/$~', $pref) === FALSE)

This results in http://example.com/index.phpwww/browse If it makes any difference, this is a CodeIgniter 1.6.1 app that I've inherited.

I tried this:

if (ereg("/$", $pref) === 0)

as @PeterM suggested and now going to http://example.com takes me to http://example.com/index.php/www/browse , but that gives me the message of "The URI you submitted has disallowed characters." Is that be a valid CodeIgniter URL? Maybe I messed something up elsewhere in the code?

I changed line 126 of codeigniter/application/config/config.php to be:

$config['permitted_uri_chars'] = 'a-z 0-9~%.:_\-';

and I still get the message.

score 3 · Accepted Answer · 2013-02-17T17:51:16.197

3

Compare it against 0, not false. preg_match returns number of matches. It returns false only on error.

edited Feb 17 '13 at 17:51

answered Feb 11 '13 at 19:31

I did that and now going to http://example.com takes me to http://example.com/index.php/www/browse , but that gives me the message of "The URI you submitted has disallowed characters." I will update my question. – Ross Fuhrman Feb 11 '13 at 19:54
It seems there is some other problem than match. Try var_dump it – Feb 11 '13 at 19:55
1

Thank you, this answered my original question. I ended up upgrading CodeIgniter to fix the rest of my problems. – Ross Fuhrman Feb 11 '13 at 22:48

score 2 · Answer 2 · 2013-07-26T11:47:37.640

2

if(substr($pref, -1) !== '/'){

}

OR:

if($pref[strlen($pref)-1] !== '/' ){
 //not found
}

edited Jul 26 '13 at 11:47

answered Feb 11 '13 at 19:33

exactly how is the end of a string supposed to contain a boolean false? OP wants to check for a `/` at the end of the line, not a false. – Marc B Feb 11 '13 at 19:37

Equivalent of ereg() call

2 Answers2