PHP: array_diff - remove one value

Question

I'm currently trying to use array_diff to remove 1 value from an array.

The code looks like this right now:

$item_id = 501;
$array = array_diff($user_items, array($item_id));

user items array: 501,501,502,502

results correctly in array: 502,502

Is it possible to remove only 1x501 instead of 2x501 value? or said differently: limit the removal by 1 value

array is then: 501,502,502

Any advice is appreciated

score 5 · Answer 1 · answered Jan 30 '13 at 23:13

5

You can use array_search to find and remove the first value:

$pos = array_search($item_id, $user_items);

if($pos !== false)
  unset($user_items[$pos]);

answered Jan 30 '13 at 23:13

nice ass

The OP wanted to remove one value only. If he wants them all out, then `array_diff` would be a better choice – nice ass Jan 30 '13 at 23:20
That *is* what my code does. Take another look or try running it and output the results. – Elliot B. Jan 30 '13 at 23:56
Yes, I see now that you're iterating the needles. Still, only one replacement is needed *in this case*, so there's no point in using a loop – nice ass Jan 30 '13 at 23:59

score 2 · Accepted Answer · edited May 23 '17 at 12:12

2

How about searching for the item, then removing it if it exists?

$key = array_search($item_id, $user_items)
if ($key !== FALSE) {
  unset($user_items[$key]);
}

Using unset isn't quite as straightforward as you'd think. See Stefan Gehrig's answer in this similar question for details.

edited May 23 '17 at 12:12

Community

answered Jan 30 '13 at 23:20

Todd Kerpelman

2 Answers2