Issue in JSON parser in iPhone?

Question

JSON Response like - {"response":{"Success":"Y","items":[{"userid":"255"}]}}

I tried to parse like this:

-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{

    NSString *jsonStr = [[NSString alloc] initWithData:mutaebleData encoding:NSUTF8StringEncoding];
    NSLog(@"JSonSTr : %@", jsonStr);
    
    SBJSON *json = [[SBJSON alloc]init];
    
    NSDictionary *dic = (NSDictionary *) [json objectWithString:jsonStr];
    NSDictionary *dic1 = (NSDictionary *) [dic objectForKey:@"response"];
    NSDictionary *dic2 = (NSDictionary *) [dic1 objectForKey:@"Success"];
    NSDictionary *dic3 = (NSDictionary *) [dic1 objectForKey:@"items"];

    NSDictionary *dic4 = (NSDictionary *) [dic3 objectForKey:@"userid"]; // App crash in this line
}

How to get userid value?

From the error it seems dic3 is an array and not a dictionary. Can you NSLog the class of dic3 and check. — Rushi, Jan 28 '13 at 07:27
Look at your JSON - the "items" key is associated with an array, not a dictionary. — Carl Veazey, Jan 28 '13 at 07:27
This isn't related to your problem, but please remove all those unsightly casts. They are usually not necessary in Objective-C and often just hide errors. — Stig Brautaset, Jan 28 '13 at 11:11

score 2 · Answer 1 · answered Jan 28 '13 at 07:27

2

This is the problem:

 NSDictionary *dic4 = (NSDictionary *) [dic3 objectForKey:@"userid"];

You should use:

NSDictionary *dic4 = (NSDictionary *) [[dic3 objectAtIndex:0] objectForKey:@"userid"];

answered Jan 28 '13 at 07:27

Ivan Alek

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The real problem is `NSDictionary *dic3 = (NSDictionary *) [dic1 objectForKey:@"items"];` since the "items" key is mapped to an array. It should be `NSArray *items = (NSArray *)[dic1 objectForKey:@"items"];`. – Carl Veazey Jan 28 '13 at 07:31
i tried this but the error comes in "No visible @interface for nsdictionary declare the selector objectatindex" – SampathKumar Jan 28 '13 at 07:55
Change this: NSDictionary *dic3 = (NSDictionary *) [dic1 objectForKey:@"items"]; into: NSArray *dic3 = (NSArray *) [dic1 objectForKey:@"items"]; – Ivan Alek Jan 28 '13 at 07:59

score 0 · Answer 2 · edited Nov 06 '21 at 02:17

0

-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{

NSString *jsonStr = [[NSString alloc] initWithData:mutaebleData encoding:NSUTF8StringEncoding];
NSLog(@"JSonSTr : %@", jsonStr);

SBJSON *json = [[SBJSON alloc]init];

NSDictionary *dic = (NSDictionary *) [json objectWithString:jsonStr];
NSDictionary *dic1 = (NSDictionary *) [dic objectForKey:@"response"];
NSDictionary *dic2 = (NSDictionary *) [dic1 objectForKey:@"Success"];
NSArray *arr3 = (NSArray *) [dic1 objectForKey:@"items"];

NSString *str = [[arr objectAtIndex:0]objectForKey:@"userid"];
NSlog(@"userid ==%@",str);
// NSDictionary *dic4 = (NSDictionary *) [dic3 objectForKey:@"userid"]; // App crash in this line
 }

edited Nov 06 '21 at 02:17

Nimantha

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answered Jan 28 '13 at 07:30

Aman Aggarwal

3,754
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26

i tried this but the error comes in nslog - Undefined symbols for architecture i386: "_NSlog", referenced from: – SampathKumar Jan 28 '13 at 07:52
Instead of NSlog type NSLog....It will solve ur pblm and do accept the answer is it's correct – Aman Aggarwal Jan 28 '13 at 08:01
I got the answer, please see above – SampathKumar Jan 28 '13 at 08:01

score 0 · Answer 3 · edited Nov 06 '21 at 02:18

0

You can add SBJSON framework files. and By parsing the by

NSDictionary *responseDict = [response JSONValue];
just parse it as normal dictionary.

NSString *userIDValue=[NSString stringWithFormat:@"%@",[[[[responseDict valueForKey:@"response"]valueForKey:@"items"]objectAtIndex:0]valueForKey:@"userid"]];

edited Nov 06 '21 at 02:18

Nimantha

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answered Jan 28 '13 at 07:48

swapnil

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score -1 · Accepted Answer · edited Nov 06 '21 at 02:17

-1

NSDictionary *dic = (NSDictionary *) [json objectWithString:jsonStr];
 NSDictionary *dic1 = (NSDictionary *) [dic objectForKey:@"response"];
 NSDictionary *dic2 = (NSDictionary *) [dic1 objectForKey:@"Success"];
 NSDictionary *dic3 = (NSDictionary *) [dic1 objectForKey:@"items"];
    
 for(NSDictionary *str in dic3)
 {
    NSLog(@"str:%@",[str valueForKey:@"userid"]);
 }

edited Nov 06 '21 at 02:17

Nimantha

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answered Jan 28 '13 at 08:00

SampathKumar

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Issue in JSON parser in iPhone?

4 Answers4