I'm somewhat confused and wondering if I've been misinformed, in a separate post I was told "New threads are only created when you make them explicitly. C++ programs are by default single threaded." When I open my program that doesn't explicitly create new threads in ollydbg I noticed multiple times that there are often 2 threads running. I wanted to understand how the message loop works without stopping up execution, the explanation I got was very insufficient at explaining how it works.
Does the message loop create a new thread or does it take up the main thread? If it takes the main thread does it do so after everything else has been executed regardless of code order? If it doesn't do this but still takes up the main thread does it spawn a new thread so that the program can execute instead of getting stuck in the message loop?
EDIT: Solved most of my questions with experimentation. The message loop occupies the main thread and any code after the code:
while (GetMessage (&messages, NULL, 0, 0))
{
TranslateMessage(&messages);
DispatchMessage(&messages);
}
return messages.wParam;
Will not execute unless something special is done to cause it to execute because the program is stuck in the message loop. Putting an infinite loop in a window procedure that gets executed causes the program to crash. I still don't understand the mystery of the multiple threads when in olly to the degree I would prefer though.