16

How to specify listening address and port in web.py? Something like:

web.application( urls, host="33.44.55.66", port=8080 )

Edit

I would like to avoid using the default web.py command line parsing

Jakub M.
  • 32,471
  • 48
  • 110
  • 179

4 Answers4

28

From API docmentation of web.py:

 module web.httpserver
    function runsimple(func,server_address=('0.0.0.0', 8080))

Runs CherryPy WSGI server hosting WSGI app func. The directory static/ is hosted statically.

Example code

import web

class MyApplication(web.application):
    def run(self, port=8080, *middleware):
        func = self.wsgifunc(*middleware)
        return web.httpserver.runsimple(func, ('0.0.0.0', port))

if __name__ == "__main__":
    app = MyApplication(urls, globals())
    app.run(port=8888)
siddharthlatest
  • 2,237
  • 1
  • 20
  • 24
18

If you're using web.py's built-in webserver, you can just append the port to the command:

python app.py 8080

I haven't tried ever with the listening address, but perhaps it will accept 1.2.3.4:8080 as the format.

Dan
  • 640
  • 5
  • 18
  • Good intuition, it accepts address too. Although, I would like to use my own command line parsing and do not mix it with default web.py command line parser – Jakub M. Jan 21 '13 at 18:32
  • Do you mean to run it from a 'normal' webserver like Apache or something? If that's the case, you'll need to play around with the Apache config to determine which address/port combo should point to your script. – Dan Jan 21 '13 at 18:35
6
URLS = ("/", index)

class index:
    def GET:
        ....

if __name__ == "__main__":
     app = web.application(URLS, globals())
     web.httpserver.runsimple(app.wsgifunc(), ("0.0.0.0", 8888))
Haozhe Xie
  • 3,438
  • 7
  • 27
  • 53
Prajapathy3165
  • 518
  • 1
  • 6
  • 13
5

you can see the follow code in wsgi.py:

server_addr = validip(listget(sys.argv, 1, ''))
if os.environ.has_key('PORT'): # e.g. Heroku
    server_addr = ('0.0.0.0', intget(os.environ['PORT']))

return httpserver.runsimple(func, server_addr)

so, you can set the web server port by add environ variable:

import os
os.environ["PORT"] = "80"
Peablog
  • 51
  • 1
  • 2