What is the % in this RegEx within this Lighthttpd configuration?

Question

  $HTTP["scheme"] == "http" {
    $HTTP["host"] =~ "^(.*)$" {
      url.redirect = ("^/folder/(.*)$" => "https://%1/$1")
    }
  }

Obviously, the %1 is inserting the host - but where is getting it from? My first thought is in from the line above it where it is matching against the host, but that doesn't seem right.

Is %1 is a built-in placeholder for the hostname or is it coming from the previous "host" match?

May be http://redmine.lighttpd.net/projects/1/wiki/docs_modredirect will help. — Rohit Jain, Jan 18 '13 at 16:41
What language is that? Please help others provide you with assistance by tagging your question appropriately. — mechanical_meat, Jan 18 '13 at 16:41
It's not a language per say. It's a lighthttpd configuration for which I tagged it and put in the title. — doremi, Jan 18 '13 at 16:42
@RohitJain Submit an answer where you quote the part about %1 and I will accept. — doremi, Jan 18 '13 at 16:47

score 1 · Accepted Answer · answered Jan 18 '13 at 16:49

From the documentation of url.redirect: -

Note that the "%1" in the url.redirect target refers to the parenthesized subexpression in the conditional regexp (.*). It does not necessarily have the meaning that "%1" would have in evhost.path-pattern (where it would mean 'top-level domain'). If url.redirect is specified within a regex conditional, % patterns are replaced by the corresponding groups from the condition regex. %1 is replaced with the first subexpression, %2 with the second, etc. %0 is replaced by the entire substring matching the regexp. See above and below for examples using % patterns.

What is the % in this RegEx within this Lighthttpd configuration?

1 Answers1