How to split a String with multiple delimiters in Java

Question

I am trying to have the desired outputs like this:

555
555
5555

by using codes:

public class Split {

/**
 * @param args
 */
public static void main(String[] args) {
    // TODO Auto-generated method stub

    String phoneNumber = "(555) 555-5555";

    String[] splitNumberParts = phoneNumber.split(" |-");


    for(String part : splitNumberParts)
        System.out.println(part);

But dont know how to get rid of the "( )" from the first element.

Thanks in advance.

Regards

have you checked with pattern and matcher classes? Once you know them you can write regular expression for extracting what you need — Hitman47, Jan 13 '13 at 16:43

score 7 · Accepted Answer · edited Feb 04 '17 at 14:48

7

StringTokenizer supports multiple delimiters that can be listed in a string as second parameter.

StringTokenizer tok = new StringTokenizer(phoneNumber, "()- ");
String a = tok.nextToken();
String b = tok.nextToken();
String c = tok.nextToken();

In your case, this will give a = 555, b = 555, c = 5555.

edited Feb 04 '17 at 14:48

Mohamed Moanis

477
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answered Jan 13 '13 at 16:42

Audrius Meškauskas

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how to put all the outputs into an array in this case please ? – Venzentx Jan 13 '13 at 17:38
1

String [] elements = new String[tok.countTokens()], then just use for loop to iterate over tokens. – Audrius Meškauskas Jan 13 '13 at 17:45

score 4 · Answer 2 · answered Jan 13 '13 at 16:42

4

why not do a replace first?

String phoneNumber = "(555) 555-5555";
String cleaned = phoneNumber.replaceAll("[^0-9]",""); // "5555555555"

Then you can use substring to get the parts you want.

answered Jan 13 '13 at 16:42

Will

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I'd prefer this solution as it doesn't require exact source formatting, giving more flexibility – Krease Jan 14 '13 at 06:06

score 1 · Answer 3 · answered Jan 13 '13 at 16:51

If you just want your digits in sequence, then you can probably make use of Pattern and Matcher class, to find all the substrings matching a particular pattern, in your case, \d+.

You would need to use Matcher#find() method to get all the substrings matching your pattern. And use Matcher#group() to print the substring matched.

Here's how you do it: -

String phoneNumber = "(555) 555-5555";

// Create a Pattern object for your required Regex pattern
Pattern pattern = Pattern.compile("\\d+");

// Create a Matcher object for matching the above pattern in your string
Matcher matcher = pattern.matcher(phoneNumber);

// Use Matcher#find method to fetch all matching pattern.
while (matcher.find()) {
    System.out.println(matcher.group());
}

score 1 · Answer 4 · answered Jan 13 '13 at 16:59

When you're using split java will return an array of string which is separated from where there was an occurence of the items which you provided, thus if you where to do a split like you are doing now, you could add something like this:

phoneNumber.split(" |-|\\(|\\) ");

But thats not very nice looking, now is it? So instead we can do something like this, which basically tells java to remove anything that isn't a number:

String[] splitNumberParts = phoneNumber.split("\\D+");

in your case, the first element in the array would be " " (space) — Venzentx, Jan 13 '13 at 17:03

How to split a String with multiple delimiters in Java

4 Answers4