Neo4jclient how to get the properties information

Question

I am new to neo4jclient, consider the below case

node:

name : Person A
age  : 25

class:

public class Person
{
    public string name { get; set; }
}

using the below query

var persons = client
    .Cypher
    .Start("n", "node(*)")
    .Return<Node<Person>>("n")
    .Results
    .Select(un => un.Data);

The above query executed successfully but in the Person object I have only 'name' property and I don't have the 'age' property. My question is: how can I get the property name and its value, for property that is not defined in the Person class.

Is it possible to get the all properties names and values?

Do you specifically not want to have an 'Age' property in your Person class? — Charlotte Skardon, Jan 11 '13 at 09:32
Yes. I will explain in another way, I want to know the properties name and it's value to the particular node. — Manivasakan, Jan 11 '13 at 11:37

score 1 · Answer 1 · answered Jan 26 '13 at 19:11

It seems to me that you want to get properties that aren't defined in your Person class. I don't believe there is a method for returning properties that aren't in your class. Neo4jClient deserializes node information and puts that into an object type you specify. For simplicity, I would just update your Person class to reflect any new properties that are added to your "Person" nodes in Neo4j.

Grabbing all property names and values from a node would take some modifications to Neo4jClient and querying Neo4j's REST API.

score 1 · Answer 2 · answered Feb 06 '13 at 09:21

I concur with @cameron-tinker, I don't think there is a way to get properties directly from the graph database, no.

The best method for solving this might be to have a class simply to deserialize your node's information into, such as PersonNode.

public class PersonNode
{
    public string Name { get; set; }
    public int Age { get; set; }
}

Then, perhaps you could have a constructor in your person class that takes in a person node to fill that out.

public Person(PersonNode node)
{
    this.name = node.Name;
}

And you'd then adjust your cypher query to pull out PersonNodes, like so:

var persons = ((IRawGraphClient)client).ExecuteGetCypherResults<Node<PersonNode>>(
    new CypherQuery("start n=node(*) return n;", 
    null,CypherResultMode.Set)) .Select(un => un.Data);

Not really a wholely original answer, I'm really just expanding on Cameron's. But I hope this helps you solve your problem.

Neo4jclient how to get the properties information

2 Answers2