Zope 2: How to save an object in debug shell?

Question

I can add/remove objects to Zope in debug shell easily, like app.manage_addProduct['OFS.Folder'].manage_addFolder('test'). However I can't figure out a way to persist the changes to the database.

Am I missing something obvious? TIA,

PS: I tried app._p_changed=1 but after exiting the shell using exit(), the changes hadn't been persisted.

Did you commit your changes? >>> import transaction; transaction.get().commit() #?? — sdupton, Jan 08 '13 at 03:04
That's it! I didn't know how to acquire a trx and commit it. Thank you! — BahmanM, Jan 08 '13 at 03:27
The Zope publisher normally commits the transaction for you, for 20x or 30x responses. For error responses the transaction is aborted. — Martijn Pieters, Jan 08 '13 at 09:25
@MartijnPieters You mean if I do for example 50 database operations, Zope will automatically commit them for me? — BahmanM, Jan 08 '13 at 12:33

score 2 · Accepted Answer · answered Jan 08 '13 at 04:42

2

You must commit the transaction, see: http://www.zodb.org/zodbbook/transactions.html

answered Jan 08 '13 at 04:42

sdupton

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Wow! That is a comprehensive guide. I assume it applies to Zope2 as well, right? – BahmanM Jan 08 '13 at 10:31

Zope 2: How to save an object in debug shell?

1 Answers1