4

Possible Duplicate:
Django-tastypie: Any example on file upload in POST?

I currently do cURL POST requests to my API like so

curl --dump-header - -H "Content-Type: application/json" -X POST --data '{"username":"theusername", "api_key":"anapikey", "video_title":"a title", "video_description":"the description"}' http://localhost:8000/api/v1/video/

but now I need to be able to add a video file to the upload. I have been looking around for a few hours about uploading files with Tastypie and I have not come up with one solid response. Do I need to add the Base64 encode? If so how? How do I acces the file after I have uploaded it with a POST request? Just normal request.FILES actions? I am not looking to save the file to the database, just get the path to the file. 

#Models.py
class Video(models.Model):
    video_uploader = models.ForeignKey(User)
    video_path = models.CharField(max_length=128)
    video_views = models.IntegerField(default=0)
    upload_date = models.DateTimeField(auto_now_add=True)
    video_description = models.CharField(max_length=860)
    video_title = models.SlugField()

I am thoroughly confused on how to implement a file upload system for Tastypie so any help would be very appreciated. Thanks!

Community
  • 1
  • 1
Ulmer
  • 1,530
  • 2
  • 17
  • 24

1 Answers1

13

Here is way to upload file by MultiPart through django-tastypie.

Models.py

class Video(models.Model):
    video_uploader = models.ForeignKey(User)
    video = models.FileField(_('Video'), upload_to='path_to_folder/') # save file to server
    video_views = models.IntegerField(default=0)
    upload_date = models.DateTimeField(auto_now_add=True)
    video_description = models.CharField(max_length=860)
    video_title = models.SlugField()

Api.py

class MultipartResource(object):
    def deserialize(self, request, data, format=None):
        if not format:
            format = request.META.get('CONTENT_TYPE', 'application/json')
        if format == 'application/x-www-form-urlencoded':
            return request.POST
        if format.startswith('multipart'):
            data = request.POST.copy()
            data.update(request.FILES)
            return data
        return super(MultipartResource, self).deserialize(request, data, format)

class VideoResource(MultipartResource, ModelResource):
   """
   Inherit this Resource class to `MultipartResource` Class
   """
   # Assuming you know what to write here 
   ...

And then through CURL

curl -H "Authorization: ApiKey username:api_key" -F "video=/path_to_video/video.mp3" -F "video_title=video title" http://localhost:8000/api/v1/video/ -v
Ahsan
  • 11,516
  • 12
  • 52
  • 79