How to let jackson generate json string using single quote or no quotes?

Question

For example, I want to generate a json string for ng-style:

<th ng-style="{width:247}" data-field="code">Code</th>

But with jackson, the result is:

<th ng-style="{&quot;width&quot;:247}" data-field="code">Code</th>

It's not easy to read.

So I want jackson to generate the json string with single quote or no quotes. Is it possible to do this?

But jackson can parse **json** strings which use single quote or no quotes for keys. — Freewind, Dec 23 '12 at 12:02

score 39 · Accepted Answer · answered Dec 27 '12 at 05:18

39

If you have control over the ObjectMapper instance, then configure it to handle and generate JSON the way you want:

final ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonGenerator.Feature.QUOTE_FIELD_NAMES, false);
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);

answered Dec 27 '12 at 05:18

Perception

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Also if you want to be able to read JSONs with single quotes with Jackson: `mapper.configure(JsonParser.Feature.ALLOW_SINGLE_QUOTES, true);` – Radu Sebastian LAZIN Jan 04 '23 at 08:52

score 4 · Answer 2 · answered Dec 10 '21 at 13:21

4

JsonGenerator.Feature.QUOTE_FIELD_NAMES

is deprecated, you can use this instead:

mapper.configure(JsonWriteFeature.QUOTE_FIELD_NAMES.mappedFeature(), false);
mapper.configure(JsonReadFeature.ALLOW_UNQUOTED_FIELD_NAMES.mappedFeature(), true);

Note that JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES is not deprecated (as of now), the corresponding JsonReadFeature is mentioned here just for completeness.

answered Dec 10 '21 at 13:21

Remigius Stalder

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Thanks! The accepted answer is deprecated now – Antonio Miranda Mar 09 '22 at 14:16

score -7 · Answer 3 · edited May 17 '16 at 16:18

The simplest and the best option is to use regular expression and update the string value.

The sample code is as listed below.

partNumberList=partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");

The complete code is as shown below

public static void main(String[] args) throws JsonParseException, JsonMappingException, 
    IOException {
    TestJack obj = new TestJack();
    //var jsonString ='{"it":"Stati Uniti d'America"}';
    //            jsonString =jsonString.replace("'", "\\\\u0027")
    ObjectMapper mapper = new ObjectMapper();
    String partNumberList = "[{productId:AS101R}, {productId:09902007}, {productId:09902002}, {productId:09902005}]";
    partNumberList = partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");
    System.out.println(partNumberList);
    mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
    List<ProductDto> jsonToPersonList = null;
    jsonToPersonList = mapper.readValue(partNumberList, new TypeReference<List<ProductDto>>() {
    });
    System.out.println(jsonToPersonList);
}

You should avoid this solution and doing things like it - all the escape sequences will be treated literally - you could possibly end up with an illegal value if there is an escaped double quote or contained single quote - YIKES! — Yoshiya, Mar 16 '19 at 12:28

How to let jackson generate json string using single quote or no quotes?

3 Answers3

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