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I'm looking for substring starting with @ and ending with the first \s occurrence. It's necessary to have @ at the beginning of the string or after space.

Example: @one bla bla bla @two @three@four #@five

Result: @one, @two, @three@four

I end up with this re: ((?<=\s)|(?<=^))@[^\s]+ which works fine in sublime text 2, but returns empty strings in python.

python code: 

re.findall(r'((?<=^)|(?<=\s))@[^\s]+', '@one bla bla bla @two @three@four #@five')
KarSho
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qubblr
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2 Answers2

2

if you are willing not to use reg expr you could try:

>>> s ="@one bla bla bla @two @three@four #@five"
>>> filter(lambda x:x.startswith('@'), s.split())
['@one', '@two', '@three@four']

This actually should be much faster...

vkontori
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Your capturing group isn't capturing the text that you are really looking for:

(?:(?<=^)|(?<=\s))(@[^\s]+)

Now, it works:

>>> re.findall(r'(?:(?<=^)|(?<=\s))(@[^\s]+)', '@one bla bla bla @two @three@four #@five')
['@one', '@two', '@three@four']
Blender
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  • It's worth mentioning that the reason for this behavior is that if capturing groups are present, `findall` returns them instead of returning the entire match (even though it *does* return the entire match if there are no groups). This is documented but it always seems to surprise people. – BrenBarn Dec 21 '12 at 06:48