Why scala compiler says that this type is used in non-specializable position?

Question

I have this method in package object:

def extractLoop[@specialized T](x: Map[T, T]) = {
    val whatever = x.head
    val stop = whatever._1
    def iteration(
            acc: Seq[T] = Seq(whatever._1, whatever._2),
            last: T = whatever._2): Seq[T] = {
        val next = x(last)
        if (next == stop) acc
        else iteration(acc :+ next, next)
    }
    iteration()
}

But I can't yet understand, why compiler (I have version 2.9.2) says type T is unused or used in non-specializable positions.?

score 5 · Accepted Answer · answered Dec 13 '12 at 19:33

I believe the reason is simply that you are using a Map[T, T] which is not specialized.

Some illustration:

scala> class MyMap[A,B]
defined class MyMap
scala> def extractLoop[@specialized T](x: MyMap[T, T]) = {
     |   sys.error("TODO")
     | }
<console>:8: warning: type T is unused or used in non-specializable positions.
       def extractLoop[@specialized T](x: MyMap[T, T]) = {
           ^
extractLoop: [T](x: MyMap[T,T])Nothing

But if you specialize MyMap for its two type parameters, you have no warning:

scala> class MyMap[@specialized A,@specialized B]
defined class MyMap
scala> def extractLoop[@specialized T](x: MyMap[T, T]) = {
     |   sys.error("TODO")
     | }
extractLoop: [T](x: MyMap[T,T])Nothing

Hmmm, seems I have understood this. – Display Name Dec 13 '12 at 19:43 — Display Name, Dec 13 '12 at 19:43

Why scala compiler says that this type is used in non-specializable position?

1 Answers1