How to get "should.be.false" syntax pass jslint?

Question

I am writing JS UT for my NodeJS code. I am using Chai as the assertion library, and I prefer the should syntax. I also use jslint to check the JS file syntax, even the JS files for UT.

Now I have a problem with jslint and Chai. In Chai, you can use:

myvalue.should.be.true;

But jslint give me:

#1 Expected an assignment or function call and instead saw an expression.

I know jslint comes with many options, but I just cannot find the right one to turn off this check.

score 74 · Answer 1 · answered Jun 28 '13 at 10:31

Just to make it clear to other readers:

You can add /*jshint expr: true*/ to the top of the test files, so it only allows it in the test files.

In the rare case that you use that kind of expressions in your code, you can add the expr: true option to the jshint config options.

score 15 · Answer 2 · answered Dec 18 '12 at 21:52

15

You can also use myvalue.should.equal(true) instead.

answered Dec 18 '12 at 21:52

Beau

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score 11 · Accepted Answer · answered Dec 11 '12 at 16:22

11

It turns our jslint is unable to solve my problem. And due to many restrictions of jslint, I turned to jshint, and the option expr saved me :P

answered Dec 11 '12 at 16:22

David S.

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I found I needed `es5:true` too. – Stephen Jul 17 '13 at 14:58
es5:true is default (now?) – hgoebl Nov 14 '13 at 21:11
seems like es5 is default now. – Sgnl Jan 19 '15 at 20:45

How to get "should.be.false" syntax pass jslint?

3 Answers3