Obtaining address of raw pointer contained in a unique pointer

Asked Dec 11 '12 at 05:26

Active Dec 11 '12 at 05:26

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I have a function, which takes a parameter which is a pointer to pointer.

 func(**pTmp);

Actually this pTmp is a raw pointer and pTmp I get is a unique pointer, so I need to pass the address of the raw pointer contained in unique pointer. I do it like this

func(&pTmp.get())

But I get this compilation error. lvalue required as unary & operand.

What am I doing Wrong?

asked Dec 11 '12 at 05:26

yogesh singh

1

You can't bind a temporary to a non-const reference. – chris Dec 11 '12 at 05:26
oh, So what should I do? – yogesh singh Dec 11 '12 at 05:29
Store the result to a local variable and pass the address of that. – chris Dec 11 '12 at 05:31
If you are stuck with this interface looks like you need to use a naked pointer, pass its address to `func` and then wrap it into a smart pointer. – Alexander Chertov Dec 11 '12 at 05:32
3

Be careful -- typically when a function takes a pointer to a pointer, it is because is trying to return a pointer, or it wants an array of pointers. – Vaughn Cato Dec 11 '12 at 05:33

Obtaining address of raw pointer contained in a unique pointer

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