Integer.parseInt() throws NumberFormatException with UTF-8 files

Question

I need to parse integers from contents of a file.

For testing my algorithms, when I give the contents of a file from a declared string

String test = "15 kuruş";

Integer.parseInt works fine. But when I read with Scanner class from a UTF-8 file it doesn't work and gives the exception

java.lang.NumberFormatException: For input string: "15"

Note: I split the string to "15" and "kuruş" so the parseInt method takes only "15" as argument.

Sample code:

    satir = satir.trim();//15 kuruş
    StringTokenizer tokenizer = new StringTokenizer(satir," ");
    System.out.println(tokenizer.countTokens());//2
    String s = tokenizer.nextToken();
    int deger = Integer.parseInt(s);//where the exception was throwed

Please show a short but complete program which demonstrates the problem. Also, check whether the '1' and '5' are the "normal" ASCII characters, or some wide variant. — Jon Skeet, Dec 07 '12 at 07:41
Ok I have edited. I guess it is not normal ASCII characters. As I indicate in the question, when I give a test string it works fine but when I read the same string from file it throws exception. — Yunus Eren Güzel, Dec 07 '12 at 07:46
@NikolayKuznetsov BOM = "Byte Order Mark" Can be present in Unicode encoded files to denote which encoding has been used. Leads to problems sometimes and is therefore ommitted often. — Fildor, Dec 07 '12 at 08:09

score 4 · Accepted Answer · answered Dec 07 '12 at 08:13

4

Your UTF-8 File probably starts with a BOM, you have to read the File with the correct encoding or get rid of it manually.

So when your 15 is not preceeded with the BOM anymore, Integer.parseInt() will work.

answered Dec 07 '12 at 08:13

jlordo

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Integer.parseInt() throws NumberFormatException with UTF-8 files

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