error: 'QDialog::QDialog(const QDialog&)' is private

Question

As the title stands I get this error within content of this snippet:

class NewTaskDialog : public QDialog

It was working just fine earlier, but error started showing up when I added method:

void MainWindow::saveButtonClicked(NewTaskDialog dialogWindow)

You should not be passing a dialog by value use a pointer instead. — drescherjm, Dec 06 '12 at 19:12

score 0 · Answer 1 · edited May 23 '17 at 12:29

0

Use a pointer to the QDialog instead. The QDialog class has the copy constructor defined as private to try prevent you from passing a QDialog by value since you should never do that.

What's the use of the private copy constructor in c++

edited May 23 '17 at 12:29

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answered Dec 06 '12 at 20:06

drescherjm

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score 0 · Accepted Answer · edited May 23 '17 at 12:29

Your syntax for saveButtonClicked creates a copy of the NewTaskDialog that's passed to it. You can't copy QWidgets unless you create a cloning function that explicitly provides the exact functionality you seek. QWidget's constructor is private.

You must pass a pointer

void MainWindow::saveButtonClicked(NewTaskDialog* dialogWindow)

or a reference. Using the pointer is the standard Qt way.

error: 'QDialog::QDialog(const QDialog&)' is private

2 Answers2