The following code results in an infinite loop with an eventual "Out of Local Stack" error Basically I am decrementing the value of GX until it is the same as MX. Sample input [[m,g,b],[w,w,w]],Path
wallBlock('w').
wallBlock('b').
item('f').
item('p').
item('m').
item('u').
item('6').
item('r').
item('g').
anyCell(Cell) :-
wallBlock(Cell).
anyCell(Cell) :-
item(Cell).
ghostPathing(Maps, Path) :-
append(Maps, NewMap),
length(Maps, N),
findGhost(NewMap, N, GX, GY),
findPacman(NewMap, N, MX, MY),
moveGhost(NewMap, N, MX, MY, GX, GY, Path).
/*FINDS THE COORDINATES OF THE GHOST W=row X=column*/
findGhost(NewMap, N, X, Y) :-
findGhostSpot(NewMap, S),
X is floor(S / N) + 1,
Y is (S mod N) +1 .
findGhostSpot(['g'|_], 0) :-
print('Found Ghost. ').
findGhostSpot(['r'|_], 0) :-
print('Found Ghost. ').
findGhostSpot(['6'|_], 0) :-
print('Found Ghost. ').
findGhostSpot([_|Tail], S) :-
findGhostSpot(Tail, S1),
S is S1+1 .
/*FINDS THE COORDINATES OF THE GHOST W=row X=column*/
findPacman(NewMap, N, X, Y) :-
findPacmanSpot(NewMap, S),
X is floor(S / N) + 1,
Y is (S mod N) + 1.
findPacmanSpot(['m'|_], 0) :-
print('Found Pacman. ').
findPacmanSpot([_|Tail], S) :-
findPacmanSpot(Tail, S1),
S is S1+1 .
/* Base Case, Ghost is on the Pacman*/
moveGhost(_, _, X, Y, X, Y, []).
/*IF PACMAN AND THE GHOST ARE IN THE SAME COLUMN*/
moveGhost(NewMap, N, MX, Y, GX, Y, ['u'|Rest]) :-
itemNext(NewMap, CN, Z),
item(Z),
moveGhost(NewMap, N, MX, Y, X, Y, Rest),
GX is X + 1,
MX < GX,
CN is ((X * N) + Y).
moveGhost(NewMap, N, MX, Y, GX, Y, ['d'|Rest]) :-
itemNext(NewMap, CN, Z),
item(Z),
moveGhost(NewMap, N, MX, Y, X, Y, Rest),
GX is X - 1,
MX > GX,
CN is ((X * N) + Y).
/*IF PACMAN AND THE GHOST ARE IN THE SAME ROW*/
moveGhost(NewMap, N, X, MY, X, GY, ['l'|Rest]) :-
itemNext(NewMap, CN, Z),
item(Z),
moveGhost(NewMap, N, X, MY, X, Y, Rest),
GY is Y + 1,
MY < GY,
CN is ((X * N) + Y).
moveGhost(NewMap, N, X, MY, X, GY, ['r'|Rest]) :-
itemNext(NewMap, CN, Z),
item(Z),
moveGhost(NewMap, N, X, MY, X, Y, Rest),
GY is Y - 1,
MY > GY,
CN is ((X * N) + Y).
itemNext([Cell|_], 0, Cell) :-
item(Cell).
itemNext([First|Rest], CN, Cell) :-
anyCell(First),
itemNext(Rest, N, Cell),
CN is N + 1.
because it is a 2d array the append turns it into 1d and the arithmetic in the NextCell takes the lenght of a row and finds the coordinates of the adjacent cell and returns the value of that cell. The ghost cannot move in that direction if the cell is a 'w' or 'b'. you can assume Maps is SQUARE!