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My task is to calculate the distance between a rectangle and the 0/0 point in an coordinate system and print a particular answer. If it's nearer than 100m (the unit of the system is meters, 1 unit = 1 meter), it should print 100m, if distance < 200m, print 101m...

I've learned that I can use the Pythagorean theorem to get the distance between two coordinates. I implemented it into my program (in Python) but I have got some trouble with the output.

Let's try an example. A rectangle with the coordinates (–400,200); (–300, 200); (–300, 300); (–400, 300) is 360m away from the point (0/0). The right output would be "103m".

Somebody asked something like this before and they said, you have to divide the distance through 100 and add it to "10{}".

print("10{}m".format(distance//100))

Actually, this works for everything below 1000. If the coordinates would be (–4000,2000); (–3000, 2000); (–3000, 3000); (–4000, 3000), the correct distance would be "3605m" and it should output "136m".

Hope you can understand my case/question!

rekire
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ThinkDifferent
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1 Answers1

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print("{:d}m".format(100+(distance//100)))

For example,

In [16]: distance = 50; "{:d}m".format(100+(distance//100))
Out[16]: '100m'

In [17]: distance = 360; "{:d}m".format(100+(distance//100))
Out[17]: '103m'

In [18]: distance = 3605; "{:d}m".format(100+(distance//100))
Out[18]: '136m'
unutbu
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  • Thank you! What does the ":d" stand for? – ThinkDifferent Nov 29 '12 at 18:15
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    `:d` formats the value as an integer. It raises a `ValueError` if the input is not an integer. The result would be the same here even if you remove the `:d`, but I wanted to emphasize that expected input is an integer. – unutbu Nov 29 '12 at 18:22