How to construct an Apache Commons Lang Range object?

Question

How can I create a Apache Commons Lang 3.1 Range<Inreger> object?

"An immutable range of objects from a minimum to maximum point inclusive."

"The objects need to either be implementations of Comparable or you need to supply a Comparator."

But when I try:

Range<Integer> range = new Range<Integer>(100, 200);

I get an error in my IDE that says required arguments are Integer, Integer, comparator.

Even though Integer implements the Comparable interface and thus I shouldn't need a extra comparator.

Can someone give me an example of how to construct the above described Range<Integer> object?

score 11 · Accepted Answer · answered Nov 29 '12 at 13:09

The constructor of Range appears to be private so a static method may be the preferred way of constructing the object.

For example, it looks like you could use the static method between to construct a Range:

Range.between(100, 200);

However there are other static methods, it just depends what you need.

score 0 · Answer 2 · answered Nov 29 '12 at 13:09

0

Range is an abstract class. Use IntRange range = new IntRange(100, 200) instead.

answered Nov 29 '12 at 13:09

looper

1

IntRange is the Range object in the old apache commons versions (before 3). I need to get intersects of ranges and this is not yet available in the old IntRange object. – WillamS Nov 29 '12 at 13:25
@WillamS: Oh, then I have an old version lying around. – looper Nov 29 '12 at 13:31

2 Answers2