what is the context of a static initializator, and how do I declare a friendship to it?

Question

class test{
    static const int veryprivate=3;
};

const int anarray[]={test::veryprivate};

g++ smartly points out that anarray is neither a function or a member function. Is it possible to fix this code keeping veryprivate private? C++11 accepted.

All it gives me is that it's private. I suppose a friended `constexpr` function that returns the value of the member would work. — chris, Nov 28 '12 at 23:50

ecatmur · Answer 1 · 2012-12-05T17:34:10.360

2

Make anarray an array reference:

class test {
    static const int veryprivate = 3;
    friend class animpl;
};
class animpl {
public:
    static const int anarray[] = { test::veryprivate };
};
auto &anarray = animpl::anarray;

edited Dec 05 '12 at 17:34

answered Dec 05 '12 at 10:03

ecatmur

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If you're going to use C++11 (to get `decltype`), why not `auto&` ? – Ben Voigt Dec 05 '12 at 15:39

what is the context of a static initializator, and how do I declare a friendship to it?

1 Answers1