Exit user impersonation by clicking a link

Asked Nov 27 '12 at 13:30

Active Nov 28 '12 at 04:47

Viewed 1,131 times

I'm trying to create a link to exit a user impersonation session. When the user clicks the exit link, he should get redirected to the admin dashboard and be logged in as himself again.

I have created a link as followed: (This doesn't work as I get an access denied screen because I'm still logged in as that normal user which doesn't have permissions to see the admin dashboard)

<a href="{{ path('AdminBundle_dashboard', {_switch_user: '_exit'}) }}">Exit</a>

But I have also tried creating the link with an absoute link and that works!

<a href="http://domain.com/app_dev.php/admin?_switch_user=_exit">Exit</a>

Although the docs say it should work by using path() http://symfony.com/doc/2.0/book/security.html#impersonating-a-user

edited Nov 28 '12 at 04:47

Mohammed H

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asked Nov 27 '12 at 13:30

mattyh88

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What is the output of {{ path('AdminBundle_dashboard', {_switch_user: '_exit'}) }}? Are you sure your previous role was admin when clicking on the first link? – Kristian Zondervan Nov 27 '12 at 15:41
Output is http://domain.com/app_dev.php/admin/?_switch_user=_exit. Yes I'm sure :) – mattyh88 Nov 27 '12 at 15:47
So output is the same as the static link but both links provide different outcome? – Kristian Zondervan Nov 27 '12 at 15:52
well almost. The dynamic link puts a "/" after "admin" – mattyh88 Nov 27 '12 at 15:56
I've implemented this feature once and I've used the Symfony routing generator (same as path in twig) without a problem. I suppose you get the exception when visiting the url domain.com/app_dev.php/admin/?_switch_user=_exit, not when rendering the path? – Kristian Zondervan Nov 27 '12 at 16:01
I've solved it by just putting Exit – mattyh88 Nov 28 '12 at 08:29

Exit user impersonation by clicking a link

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