Remove all 0s except trailing 0s from a string

Question

There are a lot of questions on removing leading and trailing 0s but i couldn't find a way to remove all 0s except trailing 0s (leading 0 or in any other place other than the end).

100010 -> 110  
010200 -> 1200  
01110  -> 1110

any suggestions ?

Convert to an integer then back to a string? – bendataclear Nov 14 '12 at 15:45 — bendataclear, Nov 14 '12 at 15:45
@bendataclear no, he wants to remove 0's in the middle too. – emartel Nov 14 '12 at 15:45 — emartel, Nov 14 '12 at 15:45

score 5 · Accepted Answer · answered Nov 14 '12 at 15:48

5

Try

echo preg_replace('/0+([1-9])/', '$1', $str);

answered Nov 14 '12 at 15:48

air4x

5,618
1
23
36

score 2 · Answer 2 · answered Nov 14 '12 at 15:48

You can use the regex [0]+(?=[1-9]) to find the zeros (using positive lookahead) and preg_replace to replace them with an empty string (assuming the number is already in string form).

$result = preg_replace("#[0]+(?=[1-9])#", "", "100010");

See it in action here

hakre · Answer 3 · 2012-11-14T16:12:06.820

You want to replace all zeroes that are not at the end of the string.

You can do that with a little regular expressions with a so called negative look-ahead, so only zeros match to be replaced that are not at the end of the string:

$actual = preg_replace('/0+(?!$|0)/', '', $subject);

The $ symbolizes the end of a string. 0+ means one or more zeroes. And that is greedy, meaning, if there are two, it will take two, not one. That is important to not replace at the end. But also it needs to be written, that no 0 is allowed to follow for what is being replaced.

Quite like you formulated your sentence:

a way to remove all 0s except trailing 0s (leading 0 or in any other place other than the end).

That is: 0+(?!$|0). See http://www.regular-expressions.info/lookaround.html - Demo.

The other variant would be with atomic grouping, which should be a little bit more straight forward (Demo):

(?>0+)(?!$)

@nickb: I was a little quick with the first answer, edited that. — hakre, Nov 14 '12 at 16:07

score 0 · Answer 4 · edited Nov 14 '12 at 16:10

0

You can use regexes to do what you want:

if(preg_match('/^(0*)(.*?)(0*)$/',$string,$match)) {
    $string = $match[1] . str_replace('0','',$match[2]) . $match[3];
}

edited Nov 14 '12 at 16:10

Iznogood

12,447
3
26
44

answered Nov 14 '12 at 15:48

lafor

12,472
4
32
35

score 0 · Answer 5 · answered Nov 14 '12 at 15:51

0

You can use regex as others suggested, or trim. Count the trailing 0's, strip all 0's, then add the trailing 0's back.

$num = 10100;
$trailing_cnt = strlen($num)-strlen(trim($num, "0"));
$num = str_replace('0','',$num).str_repeat('0', $trailing_cnt);

answered Nov 14 '12 at 15:51

Brent Baisley

12,641
2
26
39

score 0 · Answer 6 · answered Nov 14 '12 at 15:52

// original string
$string = '100010';

// remember trailing zeros, if any
$trailing_zeros = '';
if (preg_match('/(0+)$/', $string, $matches)) {
    $trailing_zeros = $matches[1];
}

// remove all zeros
$string = str_replace('0', '', $string);
// add trailing ones back, if they were found before
$string .= $trailing_zeros;

score 0 · Answer 7 · answered Nov 14 '12 at 15:55

0

here is a solution. there shoud be prettier one, but that works also.

$subject = "010200";
$match = array();
preg_match("/0*$/",$subject,$match);
echo preg_replace("/0*/","",$subject).$match[0];

answered Nov 14 '12 at 15:55

István Őri

288
2
9

score -1 · Answer 8 · answered Nov 14 '12 at 15:48

-1

Not the prettiest but it works...

$str = "01110";

if(substr($str,-1) == 0){
    $str = str_replace("0","",$str)."0";
}else{
    $str = str_replace("0","",$str);
}

echo $str; // gives '1110'

answered Nov 14 '12 at 15:48

Chris

5,516
1
26
30

Remove all 0s except trailing 0s from a string

8 Answers8