Smarty substr string skip first characters

Question

The variable $siteroot contains a string that looks like:

To get the part http://www.example.nl/ you use:

{$siteroot|substr:0:22}

But i want to skip this part and return /folder/

The length of the folder is unknown.

check my answer, you don't have to pass static position – Sibu Nov 14 '12 at 11:01 — Sibu, Nov 14 '12 at 11:01

score 9 · Accepted Answer · answered Nov 14 '12 at 10:47

9

{$siteroot|substr:22}

Should work

answered Nov 14 '12 at 10:47

Eugene

score 1 · Answer 2 · answered Nov 14 '12 at 11:00

1

{assign var="bar_at" value=$siteroot|strpos:"nl/"}
{$siteroot|substr:$bar_at+2}

answered Nov 14 '12 at 11:00

Sibu

I found a answer on another question looking similar to your answer, but I couldn't get it working. – Maarten Kuilman Nov 14 '12 at 11:04
And what if its not a nl domain? – Maarten Kuilman Nov 14 '12 at 11:08
@MaartenKuilman you just need to get the position of first instance of ,in this case "nl/" and print all values after that. I used this in one of my projects and it worked for all instances – Sibu Nov 14 '12 at 11:08
@MaartenKuilman assign that domain to variable and pass that value to strpos – Sibu Nov 14 '12 at 11:16

2 Answers2