0

I'd like to create a new real-time RSS feed using pubsubhubbub by processing an existing RSS feed which i cannot easily change. Is there a tool or approach which makes this easy? The RSS feed which i want to process does not offer pubsubhubbub links and i assume i have to poll every N seconds. Is there a readymade solution or example for this, preferably in Python? (In case you are interested i'd like to have a real-time feed of pypi.python.org updates, consumable by arbitrary other servers).

hpk42
  • 21,501
  • 4
  • 47
  • 53

2 Answers2

2

The only option I know of (excluding writing your own) is http://superfeedr.com/, but seems that they are billing subscribers too, at least on platforms they don't host.

hruske
  • 2,205
  • 19
  • 27
  • Hi, I created http://superfeedr.com . We do indeed host hubs, and subscription to these hubs is free :) However, for non pubsubhubbub enabled feeds, you'll have to pay us, but we charge less than what it'd cost you to achieve this. – Julien Genestoux Nov 08 '12 at 22:30
2

According to MvL's slides of his talk at Zope Tagung 2010 (page 19) PyPI publishes the feed with the changes of the last hour on http://pubsubhubbub.appspot.com.

Also see http://mail.python.org/pipermail/catalog-sig/2012-July/004551.html

jezdez
  • 1,499
  • 2
  • 8
  • 9
  • a good start, but why only once per hour? Isn't pubsubhubbub bout real time? – hpk42 Nov 10 '12 at 18:03
  • What I meant is that the feed shows the releases of the last hour. The PuSH hub is notified by the PyPI code automatically when a change occurs (https://bitbucket.org/loewis/pypi/src/7ffa1f091b87dd58eb3770abc6af30ec37943ba1/store.py?at=default#cl-2159), which then pulls that feed and provides any PuSH subscriber with a real time notification. – jezdez Nov 11 '12 at 13:29