Get all full visible objects on lListView

Question

I have a ListView, which contains more elements then I can display at one time.Now I want to get Index off all Elements, which are full visible ( -> excluding those that are only partially visible). At this moment I use getFirstVisiblePosition() & getLastVisiblePosition() into an for-loop to iterate them, but these method is not accurate as I want to.

Is there any better solution?

Sam · Accepted Answer · 2012-11-01T17:23:05.607

A ListView keeps its rows organized in a top-down list, which you can access with getChildAt(). So what you want is quite simple. Let's get the first and last Views, then check if they are completely visible or not:

// getTop() and getBottom() are relative to the ListView, 
//   so if getTop() is negative, it is not fully visible
int first = 0;
if(listView.getChildAt(first).getTop() < 0)
    first++;

int last = listView.getChildCount() - 1;
if(listView.getChildAt(last).getBottom() > listView.getHeight())
    last--;

// Now loop through your rows
for( ; first <= last; first++) {
    // Do something
    View row = listView.getChildAt(first);
}

Addition

Now I want to get Index off all Elements, which are full visible

I'm not certain what that sentence means. If the code above isn't the index you wanted you can use:

int first = listView.getFirstVisiblePosition();
if(listView.getChildAt(0).getTop() < 0)
    first++;

To have an index that is relative to your adapter (i.e. adapter.getItem(first).)

listView.getChildAt(index).getTop() trick work for me..thanks — CoDe, Mar 12 '15 at 12:48

score 1 · Answer 2 · answered Nov 01 '12 at 16:45

1

The way I would do this is I would extend whatever view your are passing in getView of the ListView adapter and override the methods onAttachedToWindow and onDetachedToWindow to keep track of the indexes that are visible.

answered Nov 01 '12 at 16:45

Emil Davtyan

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score 1 · Answer 3 · edited May 23 '17 at 10:30

1

Try onScrollListner and you can able to use getFirstVisiblePosition and getLastVisiblePosition.

This this link, it contain similar type of problem. I suppose you got your answer there..,.

edited May 23 '17 at 10:30

Community

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answered Nov 01 '12 at 18:15

MKB

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Thanks for the link, but this problem is exactly what I had, it gives me not the index of ListEntry what is fully visible, it returns all Items on Screen... – Kooki Nov 01 '12 at 19:37

score -1 · Answer 4 · edited Dec 12 '14 at 15:03

The above code is somewhat correct. If you need to find the completely visible location of view use below code

public void onScrollStateChanged(AbsListView view, int scrollState)  {
    // TODO Auto-generated method stub
    View v = null;

    if (scrollState == 0) {
        int first =0;
        if (view.getChildAt(first).getTop() < 0)
            first++;
        int last = list.getChildCount() - 1;
        if (list.getChildAt(last).getBottom() > list
                .getHeight())
            last--;
        // Now loop through your rows
        for ( ; first <= last; first++) {
            // Do something

            View row = view.getChildAt(first);
            // postion for your row............ 
            int i=list.getPositionForView(row);
        }
    }
        // set the margin.
}

Get all full visible objects on lListView

4 Answers4

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