Deep copy of a Drawable

Question

I have an ImageView. In its onClick I get its Drawable:

Drawable dr = ((ImageView) v).getDrawable();

And set it to a dialog's ImageView:

zoomedImage.setImageDrawable(dr);

But when I close the dialog or the activity is resumed. The image at the original position gets stretched and is shown larger than its size, leading to only a portion of the image is visible in the ImageView.

Is this a case of deep copy or there is another problem? If it is, how can do I deep copy the original Drawable so that I could set the copy to zoomed image?

Thanks in advance.

score 89 · Accepted Answer · answered Aug 23 '14 at 13:05

89

Finally I succeed! I had similar problem, when I used color filter on my drawable it changed the drawable, its very close to the solution of the other people here, but only this worked for me:

Drawable drwNewCopy = dr.getConstantState().newDrawable().mutate();

answered Aug 23 '14 at 13:05

LiranNis

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FINALLY! This is the solution to create an autonomous copy of a drawable. To mutate() the orginal drawable is not a good solution, it does not always work. Creating a new copy from the cache of the drawable (i.e. the getContantState()) works. This comment FYI for others that have spent hours upon hours on this immature/nonfinished api. – carl Dec 13 '16 at 10:23
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extension for Kotlin : fun Drawable.copy() = constantState?.newDrawable()?.mutate() – Filipkowicz Aug 02 '19 at 07:33
If I use the same `Drawable` on many views, is it better to copy like that or to get it again from resource? – Thomas Mar 10 '21 at 13:24

score 22 · Answer 2 · answered Feb 19 '14 at 13:09

I managed to copy the drawable using following code:

drawable.mutate().getConstantState().newDrawable();

Here mutate() makes the drawable mutable to avoid sharing its state, and getConstantState().newDrawable() creates a new copy.

Thus different ImageViews use different drawables and there's no stretching.

score 1 · Answer 3 · answered Oct 25 '12 at 08:27

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Use BitmapFactory to convert the drawable into bitmap separately make or perform changes on it.

answered Oct 25 '12 at 08:27

Just Variable

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score 0 · Answer 4 · answered Jan 12 '21 at 12:44

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The above solutions won't work for me, But it works

val myDrawable = DrawableCompat.wrap(view.background).mutate() as GradientDrawable
myDrawable.setColor(ContextCompat.getColor(view.context, R.color.White))

answered Jan 12 '21 at 12:44

TOUSIF

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Deep copy of a Drawable

4 Answers4

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