how to sort an array of files by keyword match of file name

Question

I have this sort function which scans a directory and lists all jpg files, how could I make it to sort only jpg files whose file-name match a specified keyword, for example to find and sort all jpg files whose name includes the keyword "toys".

   $a_img[] = array(); // return values
$keyword = "toys"; // your keyword
$allowed_types = array('jpg'); // list of filetypes you want to show  
 $dimg = opendir($imgdir);  
 while($imgfile = readdir($dimg)) {
     // check to see if filename contains keyword
    if(false!==strpos($keyword, $imgfile)){
       //check file extension
        $extension = strtolower(substr($imgfile, strrpos($imgfile, ".")+1));
        if (in_array($extension, $allowed_types)) {
        // add file to your array
        $a_img[] = $imgfile;
        }
    }   
}
// sort alphabetically by filename
sort($a_img);


   $totimg = count($a_img); // total image number  
   for($x=0; $x < $totimg; $x++)  
       { 

    $size = getimagesize($imgdir.'/'.$a_img[$x]);  
   // do whatever  

   echo $a_img[$x];  

  }

doublesharp · Answer 1 · 2012-10-25T01:35:33.210

0

You would want to check the filename for occurrences of your keyword using strpos() - http://php.net/manual/en/function.strrpos.php - and only add those files to your array. Assuming you want to sort alphabetically by filename, you sort this array using the sort() function - http://php.net/manual/en/function.sort.php

When using strpos() make sure to test for !==false otherwise your keyword at the beginning of the filename (for example "toys_picture.jpg") will return 0, which is falsey but not false.

You can also use strrpos() - http://www.php.net/manual/en/function.strrpos.php - to find the last occurrence of a . in your filename and use that for substr() should you want to support 3 and 4 character file extensions (both "jpg" and "jpeg" for example).

$imgdir = "idximages"; // directory
$keyword = "toys"; // your keyword
$allowed_types = array('jpg'); // list of filetypes you want to show  
$a_img = array(); // return values
$dimg = opendir($imgdir);  
while($imgfile = readdir($dimg)) {
    // check to see if filename contains keyword
    if(false!==strpos($imgfile, $keyword)){
        //check file extension
        $extension = strtolower(substr($imgfile, strrpos($imgfile, ".")+1));
        if (in_array($extension, $allowed_types)) {
            // add file to your array
            $a_img[] = $imgfile;
        }
    }   
}
// sort alphabetically by filename
sort($a_img);

// iterate through filenames
foreach ($a_img as $file){
    $imagesize = getimagesize($imgdir.'/'.$file);
    print_r($imagesize);
    list($width, $height, $type, $attr) = $imagesize;
}

edited Oct 25 '12 at 01:35

answered Oct 25 '12 at 00:00

doublesharp

26,888
6
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thank you so much for your help, I am totally flustered with arrays unfortunately, i just don't get it. but I tried adding your code to mine it didn't throw an error but it didn't return any results either. I have 13 images for each keyword so a set of images are named like toys.jpg, toysa.jpg, toysb.jpg, toysc.jpg, and another set of images might be named cars.jpg, carsa.jpg, carsb.jpg, etc... so I need to finda return all jpg files with the keyword toys in them. – Karen Bemus Osh Oct 25 '12 at 00:39
Have you tried adding some `echo` lines to see where the code is breaking down? – doublesharp Oct 25 '12 at 00:46
@KarenBemusOsh - my bad, I had the parameters for `if(false!==strpos($imgfile, $keyword))` backwards, it should be `strpos($haystack, $needle)`. Please see my edits. – doublesharp Oct 25 '12 at 00:50
yes, I have an echo in it, but it just returns false and shows nothing. I'd like to paste my new code in here but I can't figure out where to paste it (yeah I'm totally ignorant lol) – Karen Bemus Osh Oct 25 '12 at 00:51
ok I tried your edit code but now I'm getting the following error Warning: sort() expects parameter 1 to be array, null given – Karen Bemus Osh Oct 25 '12 at 00:58
I pasted my new code in my original post, now it's putting the Array in the image directory path and returning the error Warning: getimagesize(idximages/Array) [function.getimagesize]: failed to open stream: No such file or directory – Karen Bemus Osh Oct 25 '12 at 01:06
you need to make sure to define your array `$a_img[] = array();` - what is the value of `$imgdir`? – doublesharp Oct 25 '12 at 01:12
yes, I forgot to add the $a_img[] = array(); after I added it (see the code in my original post) it then returns the error Warning: getimagesize(idximages/Array) [function.getimagesize]: failed to open stream: No such file or directory (notice it's calling the directory as idximages/Array – Karen Bemus Osh Oct 25 '12 at 01:17
Sorry, I actually put the code into a file to test - you need `$a_img = array();`, if you use `$a_img[] = array();` then you are setting on of the array elements to another array. See updates and it should work. – doublesharp Oct 25 '12 at 01:40
Great, it would be appreciated if you could mark this as the answer now that everything is working as expected. – doublesharp Oct 26 '12 at 01:13

score 0 · Answer 2 · answered Oct 25 '12 at 00:01

0

Use strrpos to check for a substring's existence in another string

http://php.net/manual/en/function.strrpos.php

Look at the examples on that page and you should be able to match toys and exclude that from your array if it's not there

answered Oct 25 '12 at 00:01

Landon

4,088
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score 0 · Answer 3 · answered Oct 25 '12 at 00:02

0

Perhaps I've missed something but after you've said "yes, it's a JPG" you'd do something like:

if(strstr($imgfile, 'toys'))
{
  //carry on
}

answered Oct 25 '12 at 00:02

Martin Lyne

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how to sort an array of files by keyword match of file name

3 Answers3